[zeromq-dev] problem with sending and recieving in a simple PAIR setup

Tomer Eliyahu tomereliyahu1 at gmail.com
Sat Aug 18 00:44:01 CEST 2018


Aren't you missing indentation in rtx functions?

On Sat, Aug 18, 2018, 01:20 Michael Hansen <michaelsvenna at gmail.com> wrote:

> Hello, I am quite new to ZMQ which seems like a really nice library.
> However i seem to be running into some issues already.
> I have to make a setup with just 2 peers who can send to each other.
> There is no order in how the clients communicate - however in generel data
> flows
> from one to the other and commands from the other to the first.
>
> I made a small test as below but communication seem to hang up and only
> one part is sending.
> Also - sometimes when i try to run this, i get the following error:
>
> 'Resource temporarily unavailable (bundled/zeromq/src/signaler.cpp:301)
>
> Abort trap: 6'
>
>
> Here are the 2 components, what am I doing wrong?
>
>
>
>
> # ==============
> # = SERVER A
> # ==============
>
>
> import threading
> import time
> import zmq
>
>
> port = 9999
> context = zmq.Context()
> socket = context.socket(zmq.PAIR)
> socket.connect("tcp://127.0.0.1:%s" % port)
>
>
> def rtx(socket):
> print('A started receiving...')
> while 1:
> print(b'A RECEIVED : %s' % socket.recv())
>
>
> def ttx(socket):
> print('A started transmitting...')
> while 1:
> socket.send(b'Message from A')
> time.sleep(1)
>
>
> threading.Thread(target=rtx, args=(socket,)).start()
> threading.Thread(target=ttx, args=(socket,)).start()
>
>
>
>
> # ==============
> # = SERVER B
> # ==============
>
>
> import threading
> import time
> import zmq
>
>
> port = 9999
> context = zmq.Context()
> socket = context.socket(zmq.PAIR)
> socket.bind("tcp://127.0.0.1:%s" % port)
>
>
> def rtx(socket):
> print('B started receiving...')
> while 1:
> print(b'B RECEIVED : %s' % socket.recv())
>
>
> def ttx(socket):
> print('B started transmitting...')
> while 1:
> socket.send(b'Message from B')
> time.sleep(1)
>
>
> threading.Thread(target=rtx, args=(socket,)).start()
> threading.Thread(target=ttx, args=(socket,)).start()
>
> _______________________________________________
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>
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