[zeromq-dev] Concurrent send/receive with a ROUTER socket - efficient and idiomatic solution
sanjos100 at gmail.com
Sun Aug 31 11:27:53 CEST 2014
What you need is the Freelance Pattern described in Chapter 4 of the online
There is sample code - dunno if there is a Go sample.
On 31-Aug-2014 2:26 PM, "Eyal Arubas" <eyalarubas at gmail.com> wrote:
> Thanks Sean.
> Having the send and receive operations in the same thread indeed avoids
> the concurrency issue, but still we are left with polling the socket every
> few milliseconds.
> I think it's pretty much equivalent to using threads + mutex.
> I would prefer to use something along the lines of a blocking "select"
> statement on incoming and outgoing socket events; which will not abuse the
> I was hoping for a solution which, for example, allows to "select" the
> socket for inbound or outbound messages, and do one or the other.
> Thanks for your solution anyway.
> On Sun, Aug 31, 2014 at 4:03 AM, Sean Robertson <sprobertson at gmail.com>
>> I ran into this as well and came up with a potentially interesting
>> solution (though probably not idiomatic).
>> What I have is a single "dispatch" goroutine to keep all socket reads
>> and writes in one place. The dispatch interacts with two channels,
>> Requests (in) and Responses (out). On every loop it tries to read the
>> socket (with DONTWAIT), adds any incoming messages to the Requests
>> channel, and then looks in the Responses channel for outgoing messages
>> to send. No mutex necessary as the operations always happen one after
>> The rest of the code then only has to worry about reading and writing
>> these channels, which are of course thread-safe.
>> On Sat, Aug 30, 2014 at 8:35 AM, Eyal Arubas <eyalarubas at gmail.com>
>> > I am implementing a server in Go with a ROUTER socket.
>> > In one goroutine, messages are received from the socket, and
>> distributed to
>> > workers through work queues (buffered channels).
>> > Workers produce some result and queue it to another buffered channel.
>> > In another goroutine, results are dequeued and sent back to clients.
>> > The same ROUTER socket needs to be accessed from those two goroutines
>> > to receive and one to send), which creates concurrency problems; as
>> > are not threads-safe.
>> > As a demonstration, the following Go code panics randomly with:
>> >> fatal error: unexpected signal during runtime execution
>> > Link to demo:
>> > https://gist.github.com/EyalAr/117125b0e72a69584dee#file-error_demo-go
>> > My current solution is to use a poller with a short timeout, and a
>> mutex to
>> > lock access to the socket. But this seems inefficient and not
>> idiomatic. Why
>> > should I poll and lock the socket, with some arbitrary timeout, if
>> > is there?
>> > Link to my current solution:
>> > https://gist.github.com/EyalAr/117125b0e72a69584dee#file-solution-go
>> > Is there a better way?
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