[zeromq-dev] Why is the example code LGPL?
Matt Stump
mstump at goatyak.com
Tue Aug 2 06:17:42 CEST 2011
It's also in the copyright notice of all of the C source as well:
https://github.com/imatix/zguide/blob/master/examples/C/mdwrkapi.h
On Mon, Aug 1, 2011 at 6:42 PM, Steven McCoy <steven.mccoy at miru.hk> wrote:
> On 2 August 2011 08:36, Pieter Hintjens <pieterh at gmail.com> wrote:
>>
>> Matt,
>>
>> Where do you see a LGPL license? The guide says the examples are MIT
>> licensed, and the LICENSE file in the examples git also says that. Did we
>> miss something?
>
> I can see it here:
> https://github.com/imatix/zguide/blob/master/examples/C++/zmsg.hpp
> --
> Steve-o
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