[zeromq-dev] Why is the example code LGPL?

Pieter Hintjens pieterh at gmail.com
Tue Aug 2 02:36:05 CEST 2011


Where do you see a LGPL license? The guide says the examples are MIT
licensed, and the LICENSE file in the examples git also says that. Did we
miss something?

On 1 Aug 2011 17:29, "Matt Stump" <mstump at goatyak.com> wrote:
> Why is the example C++ code for zguide licensed under the LGPL?
> Wouldn't it make more sense to license it under MIT or put it into the
> public domain? LGPL makes sense for something that's intended to be
> used as a library, not example code which may be modified then
> incorporated into a shrink-wrapped product. I'll have to go through
> and re-implement all functionality instead of copying the bits I need
> and modifying the bits that don't work for my use case. Example code
> should be as permissive as possible, because the purpose of example
> code is to drive adoption. My 2 cents, for what it's worth.
> --Matt
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